这是液压缸和负载的一般模型。
Ga(s)=K*ω^2/(s*(s^2+2*ζ*ω*s+ ω^2 ))
- 本文出自液压圈，原文地 ...
请教模型：
Ga(s)=K*ω^2/(s*(s^2+2*ζ*ω*s+ ω^2 ))
Gc(s)=Kp+Kd*s+K2*s^2
CLTF(s)=Gc(s)*Ga(s)/(1+Gc(s)*Ga(s))
下面三种说法，对不对？第3种说法，对不对？
1 如果系统的开环增益用的mm/s/ 控制输出%，因为分母里有一个积分环节S,那么上面模型是一个位置系统的模型。
2 如果系统的开环增益用的mm/s/ 控制输出%，把分母里有一个积分环节S去掉, 变成
Ga(s)=K*ω^2/((s^2+2*ζ*ω*s+ ω^2 )) ，那么这个模型是一个速度控制系统的模型。
3如果系统的开环增益用的mm/ 控制输出%， 把分母里有一个积分环节S去掉, 变成
Ga(s)=K*ω^2/((s^2+2*ζ*ω*s+ ω^2 )) ，那么这个模型是一个位置控制系统的模型。
Consulting model:
Ga(s)=K*ω^2/(s*(s^2+2*ζ*ω*s+ ω^2 ))
Gc(s)=Kp+Kd*s+K2*s^2
CLTF(s)=Gc(s)*Ga(s)/(1+Gc(s)*Ga(s))
The following three statements, right?The third statement, right?
1. If the open-loop gain of the system is controlled by mm/s/output, because there is an integral link S in the denominator, then the above model is a model of a position system.
2. If the mm/s/control output of the open-loop gain of the system is used, an integral link S in the denominator is removed and converted into
Ga(s)=K*ω^2/((s^2+2*ζ*ω*s+ ω^2 )), then this model is a model of speed （velocity）control system.
3If the mm/control output of the open-loop gain of the system is used, an integral link S in the denominator is removed and converted into
Ga(s)=K*ω^2/((s^2+2*ζ*ω*s+ ω^2 )), then this model is a model of position control system.
PEN 发表于 2019-6-29 00:05
这是液压缸和负载的一般模型。
Ga(s)=K*ω^2/(s*(s^2+2*ζ*ω*s+ ω^2 ))
- 本文出自液压圈，原文地 ...
那么
这个模型是否适合液压力控系统？适合配置极点的“力控系统通用模型” 是什么样的？
that
Is this model suitable for hydraulic pressure control system? What is the "Universal Model of Force Control System" for pole placement?
then
Is this model suitable for hydraulic force control system? What is the general model of force control system suitable for pole assignment?
mayseven 发表于 2019-6-29 04:39
进行极点配置，其实就相当于赋予系统新的固有频率或阻尼比，以期望达到更快，更稳定的响应，最难的地方是 ...
选择闭环极点位置并不困难。 闭环极点位置应尽可能远离原点并尽可能接近负实轴。 然而，可以使用VCCM方程计算开环增益，并且还可以计算固有频率。 估计阻尼系数可能很困难。
Choosing the closed loop pole locations is not difficult. The closed loop pole locations should be as far away from the origin and as close to the negative real axis as possible. However, the open loop gain can be calculated using the VCCM equation and the natural frequency can also be calculated.The estimating the damping factor can be difficult. 本帖最后由 PEN 于 2019-6-30 08:52 编辑
GA（S）= K *α/（S *（S +α））。 α是电机和负载的带宽。坦克水平控制你是不对的。罐传输控制的传递函数取决于流入或流出的流体。罐液位控制的基本传递函数为K / s。这很简单。 K通常为1 / A，其中A是罐的表面积。
我帮助荷兰的一名学生解决了他需要控制坦克水平的问题。有一个泵将水泵入进入水箱2的水箱。水箱2的水位需要控制。罐中的液位很容易，但水从罐1中流出，与罐液位的平方根成比例。这不是线性的。
这同样适用于油箱2.此外，如果油箱的表面积随着油位的变化而变化，则增益K会发生变化。
https://deltamotion.com/peter/Mathcad/TwoTanks/Mathcad%20-%20t0p2%20p%20pi%20Alin's%20two%20tanks%20Cascade.pdf
我有一个YouTube频道。最受欢迎的视频与运动控制无关。最受欢迎的视频是关于如何补偿死区时间和使用简单的开关控制来控制温度。
我知道控制几乎任何东西。我知道碰巧专注于液压控制。
You are right about the servo motor.Ga(s)=K*α/(s*(s+α)).α is the bandwidth of the motor and load.You are not right about tank level control. The transfer function for tank level control depends on the fluid flowing in or flow out.The basic transfer function for tank level control is K/s. This is simple.K is usually 1/A where A is the surface area of the tank.
I helped a student in the Netherlands with a problem where he needed to control the level of a tank.There was a pump that pumped water into tank one that flowed into tank 2.The water level of tank 2 needed to be controlled. Normally controlling the fluid level in a tank is easy but the water flows out of tank 1 proportional to the square root of the tank level.This is not linear.
The same applies to tank 2.Also, the gain, K, changes if the surface area of the tank changes as the level changes.
https://deltamotion.com/peter/Mathcad/TwoTanks/Mathcad%20-%20t0p2%20p%20pi%20Alin's%20two%20tanks%20Cascade.pdf
Temperature control systems have dead time. I have a YouTube channel.The most popular video is not about motion control.The most popular video is about how to compensate for dead time and using simple on-off control to control temperature.
I am a control expert. I know how to control almost anything. I just happen to specialize in hydraulic control.
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