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发表于 2019-6-29 06:42:50
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请教模型：
Ga(s)=K*ω^2/(s*(s^2+2*ζ*ω*s+ ω^2 ))
Gc(s)=Kp+Kd*s+K2*s^2
CLTF(s)=Gc(s)*Ga(s)/(1+Gc(s)*Ga(s))
下面三种说法，对不对？ 第3种说法，对不对？
1 如果系统的开环增益用的mm/s/ 控制输出%，因为分母里有一个积分环节S, 那么上面模型是一个位置系统的模型。
2 如果系统的开环增益用的mm/s/ 控制输出%， 把分母里有一个积分环节S去掉, 变成
Ga(s)=K*ω^2/((s^2+2*ζ*ω*s+ ω^2 )) ，那么这个模型是一个速度控制系统的模型。
3 如果系统的开环增益用的mm/ 控制输出%， 把分母里有一个积分环节S去掉, 变成
Ga(s)=K*ω^2/((s^2+2*ζ*ω*s+ ω^2 )) ，那么这个模型是一个位置控制系统的模型。
Consulting model:
Ga(s)=K*ω^2/(s*(s^2+2*ζ*ω*s+ ω^2 ))
Gc(s)=Kp+Kd*s+K2*s^2
CLTF(s)=Gc(s)*Ga(s)/(1+Gc(s)*Ga(s))
The following three statements, right? The third statement, right?
1. If the open-loop gain of the system is controlled by mm/s/output, because there is an integral link S in the denominator, then the above model is a model of a position system.
2. If the mm/s/control output of the open-loop gain of the system is used, an integral link S in the denominator is removed and converted into
Ga(s)=K*ω^2/((s^2+2*ζ*ω*s+ ω^2 )), then this model is a model of speed （velocity）control system.
3 If the mm/control output of the open-loop gain of the system is used, an integral link S in the denominator is removed and converted into
Ga(s)=K*ω^2/((s^2+2*ζ*ω*s+ ω^2 )), then this model is a model of position control system.
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发表于 2019-6-30 08:06:41
